A man starts from the point P(-3,4) and reaches point Q(0,1) touching x axis at R such that PR+RQ is minimum, then point R is : ???

Assume the point to be (x,0).Using distance formulae calculate the distance.Then we get. PR=[(x+3)^2+4^2]^1/2 and RQ=[x^2+1]^1/2 .Now add PR and RQ .let RQ+PR=Y.now differentiate the eq and equate it to zero.and solve for x. Ans is (-4,0)